When Group Output binary is set to 7, which DO[#]'s will be switched ON?

When Group Output binary is set to 7, which DO[#]'s will be switched ON?

• A. 1, 2, 3
• B. 1, 2, 3, 4
• C. 1, 2, 3, 4, 5
• D. 2, 3, 4, 5

Answer: (A)

When Group Output binary is set to 7, the binary representation of the number indicates which Digital Outputs (DO) will be activated. The number 7 in binary is represented as 0111. Each bit in this binary representation corresponds to a specific DO, with the least significant bit representing DO[1] and the most significant bit (among those being considered) representing DO[4]. Therefore, for the binary 0111: - The first bit corresponds to DO[1], which is ON. - The second bit corresponds to DO[2], which is ON. - The third bit corresponds to DO[3], which is ON. - The fourth bit corresponds to DO[4], which is OFF. This means that only DO[1], DO[2], and DO[3] will be switched ON, as the fourth bit indicates that DO[4] will remain OFF. Consequently, the group output configuration of 7 effectively results in the activation of DO[1], DO[2], and DO[3], validating why this choice is the correct answer.

When Group Output binary is set to 7, the binary representation of the number indicates which Digital Outputs (DO) will be activated. The number 7 in binary is represented as 0111. Each bit in this binary representation corresponds to a specific DO, with the least significant bit representing DO[1] and the most significant bit (among those being considered) representing DO[4].

Therefore, for the binary 0111:

• The first bit corresponds to DO[1], which is ON.

• The second bit corresponds to DO[2], which is ON.

• The third bit corresponds to DO[3], which is ON.

• The fourth bit corresponds to DO[4], which is OFF.

This means that only DO[1], DO[2], and DO[3] will be switched ON, as the fourth bit indicates that DO[4] will remain OFF. Consequently, the group output configuration of 7 effectively results in the activation of DO[1], DO[2], and DO[3], validating why this choice is the correct answer.